3x-17=x^2+25

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Solution for 3x-17=x^2+25 equation: 



3x-17=x^2+25

We move all terms to the left:

3x-17-(x^2+25)=0

We get rid of parentheses

-x^2+3x-25-17=0

We add all the numbers together, and all the variables

-1x^2+3x-42=0

a = -1; b = 3; c = -42;
Δ = b2-4ac
Δ = 32-4·(-1)·(-42)
Δ = -159
Delta is less than zero, so there is no solution for the equation

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